grundwissen:loesung1a
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| grundwissen:loesung1a [2022/08/25 07:55] – martin | grundwissen:loesung1a [2022/08/25 07:55] (current) – martin | ||
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| ====== Lösung zu Aufgabe 1 ====== | ====== Lösung zu Aufgabe 1 ====== | ||
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| - | $$R = \frac{U}{I} \Rightarrow I = \frac{U}{R} = \frac{5 V}{2 k\Omega} = 2,5 mA \mathrm{\frac{m}{s^{-2}}}$$ | + | $$R = \frac{U}{I} \Rightarrow I = \frac{U}{R} = \frac{5 V}{2 k\Omega} = 2,5 mA$$ |
| Die Verlustleistung beträgt | Die Verlustleistung beträgt | ||
| $$P = U\cdot I = 5 V \cdot 2,5 mA = 12,5 mW$$ | $$P = U\cdot I = 5 V \cdot 2,5 mA = 12,5 mW$$ | ||
grundwissen/loesung1a.1661414111.txt.gz · Last modified: by martin
